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Prob 15. To find ye
Gravity of any given plaine in respect of any given axis, given in position
when it may bee done.
Resol: Suppose ek to bee ye
Axis of Gravity, acb the given plaine,
cb=y, & db=z to bee ordinatly applyed at any angles to ab=x. Bisect
cb at m & draw mn⊥ek. Now, since [cb×mn] is ye
gravity of ye
line [cb], (by lem 1 & 2); if I make cb×mn=db=z, every line db shall
designe ye
Gravity of its correspondent line cb, yt
is, ye
superficies adb
shall designe ye
Gravity of ye
superficies acb. Soe yt
finding ye
quantity
of yt
superficies adb (by prob 7) I find ye
gravity of ye
sup
[illeg]e
|er|ficies acb.
Example 1 If ac is a Parabola; soe yt
, ab[illeg] bc=[4], & z=d[a]∥k
parallelTo;ak=axis rx=yy, & ye
axis ak is ∥ dcb. &,
[illeg]
nb⊥ak, &
yt
, ab∶nb∷d∶e. Then is bc×nb=y×.
Or eerx3=ddzz, is ye
nature of ye
curve line ad. whose
area (were
[illeg]
abd a right angle would be but now it) is , (by
prob 7) wch
is ye
weight of ye
area acb in respect of ye
axis ak.
Examp: 2 If ac is a Circle
Prob 16. To find ye Axes of Gravity i |o|f any Plaines
Resol. Find ye
quantity of ye
Plaine (by Prob 7) \
wch
call A/ & ye
quantity of its gravity in respect
of any axis (by prob 15) wch
call B
[illeg]
. & parallell to yt
axis draw a line whose distance
from it shall bee
[illeg]
. That line shall bee an Axis of Gravity of ye
given plain
Or If you y cannot find ye
quantity of the plane: Then
find its gravitys in respect of two divers axes (AB & AC) wch
gravitys
call B[illeg] & C & D. & through |(A)|
ye
intersection of those axes draw
a line AD wth
this condition yt
ye
distances (DB & DC) of any one
of its points (D) from the said axes (AB & AC), bee in such proportion as \to/ the gravitys
of the plane. That line (AD) shall bee an axis of gravity of ye
said plane EF.