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Prob 15. To find ye Gravity of any given plaine in respect of any given axis, given in position
when it may bee done.

Resol: Suppose ek to bee ye Axis of Gravity, acb the given plaine, Figure 1
cb=y, & db=z to bee ordinatly applyed at any angles to ab=x. Bisect
cb at m & draw mn⊥ek. Now, since [cb×mn] is ye gravity of ye
line [cb], (by lem 1 & 2); if I make cb×mn=db=z, every line db shall
designe ye Gravity of its correspondent line cb, yt is, ye superficies adb
shall designe ye Gravity of ye superficies acb. Soe yt finding ye quantity
of yt superficies adb (by prob 7) I find ye gravity of ye sup [illeg]e |er|ficies acb.

Example 1 If ac is a Parabola; soe yt , ab[illeg] bc=[4], & z=d[a]∥k Figure 2
parallelTo;ak=axis rx=yy, & ye axis ak is ∥ dcb. &, [illeg]
nb⊥ak, & yt , ab∶nb∷d∶e. Then is bc×nb=y× e × ab d = ex d rx = z .
Or eerx3=ddzz, is ye nature of ye curve line ad. whose
area (were [illeg] abd a right angle would be 2 e 5 d x 5 2 y 1 2 = 2 e 5 d r x 5 but now it) is 2 ee 5 dd r x 5 , (by
prob 7) wch is ye weight of ye area acb in respect of ye axis ak.

Examp: 2 If ac is a Circle

Prob 16. To find ye Axes of Gravity i |o|f any Plaines

Resol. Find ye quantity of ye Plaine (by Prob 7) \ wch call A/ & ye quantity of its gravity in respect
of any axis (by prob 15) wch call B [illeg] . & parallell to yt axis draw a line whose distance
from it shall bee [illeg] A B . That line shall bee an Axis of Gravity of ye given plain

Or If you y cannot find ye quantity of the plane: Then Figure 3
find its gravitys in respect of two divers axes (AB & AC) wch gravitys
call B[illeg] & C & D. & through |(A)| ye intersection of those axes draw
a line AD wth this condition yt ye distances (DB & DC) of any one
of its points (D) from the said axes (AB & AC), bee in such proportion as \to/ the gravitys
of the plane. That line (AD) shall bee an axis of gravity of ye said plane EF.